sin(a+π⼀4)sin(a-π⼀4)=1⼀3,则cos4a=?

2025-12-18 03:00:56
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回答1:

sin(a+π/4)sin(a-π/4)
=(sinacosπ/4+cosasinπ/4)(sinacosπ/4cosasinπ/4)
=[√2/2(sina+cosa)][√2/2(sina-cosa)]
=1/2(sin²a-cos²a)
=1/3
sin²a-cos²a=2/3
cos2a=cos²a-sin²a=-2/3
cos4a=2cos²2a-1
=2×(-2/3)²-1
=-1/9