rs.open "select top 1 len(love_article.username) as

2025-12-16 12:45:33
推荐回答(1个)
回答1:

rs.open "select top 1 len(love_article.username) as a,love_article.id,love_main.photo_x from love_article join love_main on love_article.userid=love_main.id order by love_article.username desc",conn,1,1

中间的top 1len(*****)不要分开,会错